现有程序:listA=[("math",80),("chinese",90),("phyical",96)]classes,score=zi

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现有程序:listA=[("math",80),("chinese",90),("phyical",96)]classes,score=zip(*listA)print(classes)输出为:()

A.("math","chinese","phyical")

B.[("math","chinese","phyical")]

C.[(80.90.96)]

D.(80.90.96)

参考答案:

答案:A