现有程序:listA=[("math",80),("chinese",90),("phyical",96)]classes,score=zi

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现有程序:listA=[("math",80),("chinese",90),("phyical",96)]classes,score=zip(*listA)a,b,c=scoreprint(c)输出为:()

A.math

B.chinese

C.96

D.90

参考答案:

答案:C