现有程序:listA=[("math",80),("chinese",90),("phyical",96)]classes,score=zi
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现有程序:listA=[("math",80),("chinese",90),("phyical",96)]classes,score=zip(*listA)print(score)输出为:()
A.("math","chinese","phyical")
B.[("math","chinese","phyical")]
C.[(80.90.96)]
D.(80.90.96)
参考答案: