二进制数11101110B与01110111B的“与”、“或”和“异或”结果是()
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二进制数11101110B与01110111B的“与”、“或”和“异或”结果是()
A.01100110B.10011001B.11111111B
B.11111111B.10011001B.01100110B
C.01100110B.01110111B.10011001B
D.01100110B.11111111B.10011001B
参考答案: